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-16.1x^2+40x+4=0
a = -16.1; b = 40; c = +4;
Δ = b2-4ac
Δ = 402-4·(-16.1)·4
Δ = 1857.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-\sqrt{1857.6}}{2*-16.1}=\frac{-40-\sqrt{1857.6}}{-32.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+\sqrt{1857.6}}{2*-16.1}=\frac{-40+\sqrt{1857.6}}{-32.2} $
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